A charge Q is situated at the centre of a cube. The electric flux through one of the faces of the cube is

Given data: A charge q enclosed inside a cube 

Concept used: Electric flux 

Detailed solution:

Electric flux due to charge q inside the cube is

$\varphi =\frac{Q_{enclosed}}{{\epsilon }_0}=\frac{q}{{\epsilon }_0}$

Therefore, Flux through each face= $\frac{1}{6}$ total flux through the cube

$=\frac{q}{6{\epsilon }_0}$