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A charge q moves in a region where electric field E and magnetic field B both exist, then the force on it is

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$q B + q (B \times v)$

$q E + q (v \times B)$

$q B + q (E \times v)$

$q (v \times B)$

answer is B.

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Detailed Solution

$\bar{F} = {\bar{F}}_{e} + {\bar{F}}_{m}$

$\bar{F} = \bar{E} q + q (\bar{V} \times \bar{B})$

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