Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5

Q.

A charged capacitor when filled with a dielectric K = 3 has charge Q0, voltage V0 and field E0. If the dielectric is replaced with another one having K = 9, the new values of charge, voltage and electric field will be respectively

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

a

Q0, V03, 3E0

b

3Q0, 3V0, 3E0

c

Q0, V03, E03

d

Q0, 3V0, 3E0

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

When charged capacitor is filled with a dielectric material of dielectric constant K, then charge remains constant, V becomes 1K times and E becomes 1K times.

So, new value of charge is Q0.

New value of V=V0×39=V03

New value of E=E0×39=E03

Watch 3-min video & get full concept clarity

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon