A charged cork ball of mass 1g is suspended on a light string in the presence of a uniform electric field as shown. When E→=(3i^+5j^)×105NC−1, the ball is in equilibrium at θ=37∘. T is the tension in the string and q is the charge on the ball approximately is (Take sin37∘=0.60 and g=10ms−2)

Tsinθ=qEα⇒T×0.6=q×3×105 q=2×10−6T Tcosθ+qEy=mg T(0.8)+q×5×105=1×10−3×10 ⇒T=5.55×10−3N q=11.1nc≈11nc

A charged cork ball of mass 1g is suspended on a light string in the presence of a uniform electric field as shown. When E→=(3i^+5j^)×105NC−1, the ball is in equilibrium at θ=37∘. T is the tension in the string and q is the charge on the ball approximately is (Take sin37∘=0.60 and g=10ms−2)

Tsinθ=qEα⇒T×0.6=q×3×105 q=2×10−6T Tcosθ+qEy=mg T(0.8)+q×5×105=1×10−3×10 ⇒T=5.55×10−3N q=11.1nc≈11nc

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A charged cork ball of mass 1g is suspended on a light string in the presence of a uniform electric field as shown. When $\vec{E} = (3 \hat{i} + 5 \hat{j}) \times 10^{5} N C^{- 1}$ , the ball is in equilibrium at $θ = 37^{\circ}$ . T is the tension in the string and q is the charge on the ball approximately is
(Take $\sin 37^{\circ} = 0.60 a n d g = 10 m s^{- 2}$ )

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q = 12 nC

q = 11 nC

$T = 4.55 \times 10^{- 3} N$

$T = 5.55 \times 10^{- 3} N$

answer is A, C.

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$T \sin θ = q E_{α} \Rightarrow T \times 0.6 = q \times 3 \times 10^{5} q = 2 \times 10^{- 6} T T \cos θ + q E_{y} = m g T (0.8) + q \times 5 \times 10^{5} = 1 \times 10^{- 3} \times 10 \Rightarrow T = 5.55 \times 10^{- 3} N q = 11.1 n c \approx 11 n c$