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A charged disc of radius 3m has charge density $σ$ . Electric field at a distance of 4m from its centre on axis is _____

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$\frac{σ}{10 ε_{0}}$

$\frac{σ}{8 ε_{0}}$

$\frac{3 σ}{5 ε_{0}}$

None

answer is B.

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Detailed Solution

The field due to disc is given by $E = \frac{σ}{2 ε_{0}} [1 - \frac{x}{\sqrt{x^{2} + R^{2}}}]$

$E = \frac{σ}{2 ε_{0}} [1 - \frac{4}{\sqrt{4^{2} + 3^{2}}}] = \frac{σ}{10 ε_{0}}$

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