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Q.

A charged non-conducting thin Disc of radius R is spinning with an angular speed 'ω‘. Surface charge density of disc is ’σ' then magnetic field at its centre is.

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a

μ0σR2ω

b

μ0σωR2

c

μ0σωR22

d

μ0σωR2π

answer is B.

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Detailed Solution

dI=2πydyσω2π=σωydy
dB=μ02dIy2h2+x23/2
=μ0σω20Ry3y2+x23/2dy; Bcentre =μ0σωR2
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