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A charged particle (charge = q, mass =m) is rotating in a circle of radius ‘R’ with uniform speed “V” ratio of magnetic moment $(μ)$ to the angular momentum (L) is

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$\frac{q}{m}$

$\frac{q}{2 m}$

$\frac{2 q}{m}$

$\frac{q}{4 m}$

answer is B.

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Detailed Solution

$μ = i A$ here $A = π R^{2}$ and $i = \frac{q v}{2 π R}$

$L = m v R$

$∴ \frac{μ}{L} = \frac{q}{2 m}$

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