Q.

A charged particle going around in a circle can be considered to be a current loop. A particle, of mass m carrying charge q is moving in a plane with speed v under the influence of magnetic field B¯. The magnetic moment of this moving particle:

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a

mV2B-2B2

b

mv2B-2πB2

c

mv2B-B2

d

mv2B-2B2

answer is D.

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Detailed Solution

Question Image

Length of the circular path, =2πr

Current, i˙=qT=qv2πr 

Magnetic moment M = Current × Area = i×πr2=qV2πr×πr2

M=12 q.v.r 

Radius of circular path in magnetic field, r=mVqB

M=12qv×mvqBM=mv22B

Direction of M¯ is opposite of B¯ therefore,

M¯=mv2 B2B2

(By multiplying both numerator and denominator by B).

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