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Q.

A charged particle, having charge  q1 accelerated through a potential difference V enters a perpendicular magnetic field in which it experiences a force F. If V is increases to 5V. The particle will experience a force

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a

F/5

b

5F

c

5F

d

F

answer is D.

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Detailed Solution

KE=12mv2=qV       v=2gM=v        F∝v      F'F=5vu =5×10−4

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