A charged particle having drift velocity of 7.5×10−4m s−1 in an electric field of 3×10−10Vm−1, has a mobility (in m2V−1s−1) of magnitude....

μ=VdE=7.5×10−43×10−10⇒μ=2.5×106

A charged particle having drift velocity of 7.5×10−4m s−1 in an electric field of 3×10−10Vm−1, has a mobility (in m2V−1s−1) of magnitude....

μ=VdE=7.5×10−43×10−10⇒μ=2.5×106

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A charged particle having drift velocity of $7 .5 \times 10^{- 4} m s^{- 1}$ in an electric field of $3 \times 10^{- 10} {Vm}^{- 1},$ has a mobility (in $m^{2} V^{- 1} s^{- 1}$ ) of magnitude....

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$2.5 \times 10^{6}$

$2.5 \times 10^{- 6}$

$2.25 \times 10^{- 15}$

$2.25 \times 10^{15}$

answer is A.

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$\begin{array}{l} μ = \frac{V_{d}}{E} = \frac{7 .5 \times 10^{- 4}}{3 \times 10^{- 10}} \\ \Rightarrow μ = 2 .5 \times 10^{6} \end{array}$

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A charged particle having drift velocity of 7.5×10−4m s−1 in an electric field of 3×10−10Vm−1, has a mobility (in m2V−1s−1) of magnitude....

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A charged particle having drift velocity of $7 .5 \times 10^{- 4} m s^{- 1}$ in an electric field of $3 \times 10^{- 10} {Vm}^{- 1},$ has a mobility (in $m^{2} V^{- 1} s^{- 1}$ ) of magnitude....