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Q.

A charged particle is suspended in equilibrium in a uniform vertical electric field of intensity 20000 V/m. If mass of the particle is 9.6×10−16 kg, the charge on it and excess number of electrons on the particle are respectively (g=10 m/s2)

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a

5.8×10−19C, 4

b

4.8×10−19C, 3

c

2.8×10−19C, 1

d

3.8×10−19C, 2

answer is A.

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Detailed Solution

In equilibrium 

QE=mg⇒n=mgEe=9.6×10−16×1020,000×1.6×10−19=3

charge 3e

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