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Q.

A charged particle moving in a uniform magnetic field in a circular path. The energy of the particle is doubled. If the initial radius of the circular path was R, The radius of the new circular path after the energy is doubled will be $\sqrt{x} R . T h e n x =$

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answer is 2.

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Detailed Solution

$r \propto \sqrt{K . E} \Rightarrow \frac{r_{1}}{r_{2}} = \sqrt{\frac{K . E_{1}}{K . E_{2}}}$

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