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Q.

A charged particle of change 4mc enters a uniform magnetic field of inductionB¯=4i^+yj^+zk^  tesla with a velocity v¯=2i^+3j^−6k^ . If the particle continues to move un deviated, then the strength of the magnetic field induction (B) is ____ tesla

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a

3.5

b

14

c

28

d

2

answer is C.

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Detailed Solution

F=0⇒V→×B→=0

⇒24=3y=−6z

⇒y=6 and z=−12

B→=4i^+6j^−12k^

B=42+62+(−12)2

=16+36+144

=196=14 T

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