A charged particle of mass $10^{-3} kg$ and charge $10^{-5} C$ enters a magnetic field of induction 1 T such that its direction of motion is perpendicular to the direction of magnetic field. If ${g=10ms}^{- 2}$ , for what value of velocity will it pass straight through the field without deflection?

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$10^{3} {ms}^{-1}$

$10^{6} {ms}^{-1}$

${1ms}^{- 1}$

$10^{-3} {ms}^{-1}$

answer is B.

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Detailed Solution

Since the charged particle passes straight without deflection, therefore

$Bqv=mg v= \frac{mg}{Bq} = \frac{10^{-3} ×10}{{1×10}^{-5}} {=10}^{3} {ms}^{-1}$

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