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Q.

A charged particle of mass  5×10−5kg is held stationary in space by placing it in an electric field of strength  107NC−1 directed vertically downwards. The charge on the particle is

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a

5×10−5μC

b

−5×10−5μC

c

20×10−5μC

d

−20×10−5μC

answer is B.

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Detailed Solution

QE=mg⇒Q=mgE=5×10−5×10107=5×10−5μC

Since electric field is acting downward so for balance charge must be negative.

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