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Q.

A charged particle of mass m and charge q enters a magnetic field B with a velocity v at an angle $θ$ with the direction of B. The radius of the resulting path is

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a

$\frac{mvtan θ}{qB}$

b

$\frac{mv}{qBsin θ}$

c

$\frac{mv}{qB}$

d

$\frac{mvsin θ}{qB}$

answer is A.

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Detailed Solution

$R = \frac{mvsin θ}{qB}$

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