A charged particle of mass m=2kg and charge 1 µC is projected from a horizontal ground at an angle $θ = 45^{0}$ with speed 10ms^-1 . In space, a horizontal electric field toward the direction of projection $E = 2 \times 10^{7} {NC}^{- 1}$ exists. The range of the projectile is

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

answer is 20.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

$a_{x} = \frac{qE}{m} = \frac{10^{- 6} \times 2 \times 10^{7}}{2} = 10 {ms}^{- 2}$

Time of flight T $= \frac{2 usin θ}{g} = \frac{2 \times 10 \times \frac{1}{\sqrt{2}}}{10} = \sqrt{2} s$
Hence, $R = u_{x} T + \frac{1}{2} a_{x} T^{2} = (10 \cos 45) \times T + \frac{1}{2} a_{x} T^{2} = \frac{10}{\sqrt{2}} \times \sqrt{2} + \frac{1}{2} \times 10 \times 2 = 20 m$