A charged particle of specific charge qm=α is released from origin at time t=0 with velocity V¯=V0i^+j^ in uniform magnetic field B¯=B0i^. Co-ordinates of the particle at time t=πB0α are.

α=qm, Path of the particle will be a helix of time period T=2πmBoq=2πB0α The given time t=πB0α=T2∴ Coordinates of particle at time t=T2Would be VxT/2,0,−2rHere, r=mV0B0q=v0B0α ∴The coordinates are VoπB0α,0,−2V0Boα .

A charged particle of specific charge qm=α is released from origin at time t=0 with velocity V¯=V0i^+j^ in uniform magnetic field B¯=B0i^. Co-ordinates of the particle at time t=πB0α are.

α=qm, Path of the particle will be a helix of time period T=2πmBoq=2πB0α The given time t=πB0α=T2∴ Coordinates of particle at time t=T2Would be VxT/2,0,−2rHere, r=mV0B0q=v0B0α ∴The coordinates are VoπB0α,0,−2V0Boα .

AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

A charged particle of specific charge $(\frac{q}{m}) = α$ is released from origin at time $t = 0$ with velocity $\bar{V} = V_{0} (\hat{i} + \hat{j})$ in uniform magnetic field $\bar{B} = B_{0} \hat{i}$ . Co-ordinates of the particle at time $t = \frac{π}{B_{0} α}$ are.

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

$(\frac{v_{0}}{2 B_{0} α}, \frac{\sqrt{2} . v_{0}}{α B_{0}}, \frac{- v_{0}}{B_{0} α})$

$(\frac{- v_{0}}{2 B_{0} α}, 0, 0)$

$(0, \frac{2 v_{0}}{B_{0} α}, \frac{v_{0} π}{2 B_{0} α})$

$(\frac{v_{0} π}{B_{0} α}, 0, \frac{- 2 v_{0}}{B_{0} α})$

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

$α = \frac{q}{m}$ ,

Path of the particle will be a helix of time period
$T = \frac{2 π m}{B_{o} q} = \frac{2 π}{B_{0} α}$

The given time $t = \frac{π}{B_{0} α} = \frac{T}{2}$
$∴$ Coordinates of particle at time $t = \frac{T}{2}$
Would be $(V_{x} T / 2, 0, - 2 r)$
Here, $r = \frac{m V_{0}}{B_{0} q} = \frac{v_{0}}{B_{0} α}$
$∴$ The coordinates are $(\frac{V_{o} π}{B_{0} α}, 0, \frac{- 2 V_{0}}{B_{o} α})$ .