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A charged particle revolves in circular path in uniform magnetic field after accelerating by a potential difference of V volts. Choose the correct options if V is doubled

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kinetic energy of particle will become two times

radius in circular path will become two times

radius in circular path will become $\sqrt{2}$ times

angular velocity will remain unchanged

answer is A, C, D.

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Detailed Solution

$KE = q V$ or $KE \propto V$

$r = \frac{\sqrt{2 q V m}}{B q}$

or $r \propto \sqrt{V}$

$T = \frac{2 π m}{B q}$

or T is independent of V.

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