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Q.

A charged particle travels along a straight line with a speed v in a region where both electric field E and magnetic field B are present. It follows that vB

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a

E=B and the two fields are perpendicular 

b

E=vB and the two fields are perpendicular 

c

B=vE and the two fields are parallel

d

B=vE and the two fields are perpendicular 

answer is B.

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Detailed Solution

qE+qv×B=0 E=B×v

or, EB

Further, E=Bv sin 90°

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