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A charged sphere of radius 0.02 m has charge density of 1 Cm^–2. The work done when a charge of 40 nC is moved from infinity to a point that is at a distance of 0.04 m from the center of the sphere

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1.44πJ

2 J

14.4πJ

1.44J

answer is C.

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Detailed Solution

$\begin{array}{l} V = \frac{σ}{4 {πε}_{0}} \frac{4 {πr}^{2}}{R} \\ W = qV = 1 \times 9 \times 10^{9} \times \frac{4 π (0 .02)^{2}}{(0 .04)} = 14 .4 πJ \end{array}$

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