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A charge $Q = 10 μC$ is distributed uniformity over the circumference of a ring of radius $3 m$ placed on $x - y$ plane with it’s centre at origin. The electric potential at a point $p (0, 0, 4 m)$ is:

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$1.8 \times 10^{4} V$

$2.2 \times 10^{4} V$

$3.6 \times 10^{4} V$

$3 \times 10^{4} V$

answer is C.

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Detailed Solution

$q = 10 μ C = 10 \times 10^{- 6} C$

$r a d i u s = 3 m$

distance of the point from the circumference of the ring,

$d = \sqrt{3^{2} + 4^{2}} = 5 m$

$potential is given as, V = \frac{kq}{d}$

$substituting q and d values, we get V = 1.8 x 10^{4} volt$

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