Book Online Demo

Check Your IQ

Try Test

Courses

Offline Centres

A child having a mass of $35 kg$ sitting on a trolley of mass $5 kg$ . The trolley is moved with an initial velocity of $4 m / s$ by applying a force. The trolley came to rest after travelling a distance of $16 m .$ Find the work done on the trolley.

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

160 J

320 J

640 J

1280 J

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

The amount of work done on the trolley is

320 Joules

.
Given, the initial velocity of the trolley,

u = 4 m / s

Final velocity of the trolley,

v = 0 m / s

Distance travelled by the trolley,

s = 16 m

From third equation of the motion,

{\Rightarrow v}^{2} - u^{2} = 2 as

Acceleration of the trolley is given by,

\Rightarrow a = \frac{(v^{2} -^{} u^{2})}{2 s}

\Rightarrow a = \frac{0 - (4)^{2}}{2 \times 16}

\Rightarrow a = \frac{16}{2 \times 16}

\Rightarrow a = - 0.5 m / s^{2}

Work done on the trolley by the force

\Rightarrow W = Fs

\Rightarrow W = mas

\Rightarrow W = (35 + 5) \times (0.5) \times 16

\Rightarrow W = 20 \times 16

\Rightarrow W = 320 J

Therefore, the amount of work done on the trolley is

320 Joules

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE