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A child is standing at one end of a long trolley moving with a speed v on a smooth horizontal track. If the child starts running towards the other end of the trolley with a speed u, the centre of mass of the system (trolley + child) will move with a speed

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zero

$(v + u)$

$(v - u)$

$v$

answer is D.

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Detailed Solution

The speed of the centre of mass of the system will remain unchanged (= v).

The speed of the centre of mass of a system can change only if a net external force acts on it.

The forces involved (such as the action and reaction and frictional forces), when the child runs on the trolley, are internal to the (trolley + child) system.

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