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Q.

A child is standing with folded hands at the centre of a platform rotating about its central axis. The K.E of the system is K. The child now stretches his arms so that the M.I of the system doubles. The K.E of the system now is k/n then find n

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answer is 2.

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Detailed Solution

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$KE = \frac{L^{2}}{2 I} \Rightarrow E \propto \frac{1}{l}$

$\frac{E_{2}}{E_{1}} = \frac{I_{1}}{I_{2}} \Rightarrow \frac{E_{2}}{E} = \frac{I}{2 I}$

$∴ E_{2} = \frac{E_{1}}{2} = \frac{K}{2}$

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A child is standing with folded hands at the centre of a platform rotating about its central axis. The K.E of the system is K. The child now stretches his arms so that the M.I of the system doubles. The K.E of the system now is k/n then find n