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A child of mass 5 kg is going round a merry-go-round that makes 1 rotation in 3.14 s. The radius of the merry-go-round is 2 m . The centrifugal force on the child will be

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40 N

80 N

50 N

100 N

answer is A.

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Detailed Solution

m = 5kg
R = 2m
T = 3.14 sec

$\begin{array}{l} F = {mRω}^{2} \\ F = mR {(\frac{2 π}{T})}^{2} \end{array}$
$F = 10 \times 4 \times \frac{(3.14)^{2}}{(3.14)^{2}} \to F = 40 N$

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