A child pulls a toy car through a distance of $10 metres$ on a horizontal floor. The string held in the child’s hand makes an angle of $60^{0}$ with the horizontal surface. If the force applied by the child is $10 N$ , then which of the following is the work done by the child in pulling the toy car?

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70 joule

50 joule

40 joule

None of these

answer is B.

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Detailed Solution

The work done by the child in pulling the toy car is

50 Joule

.
Applied force and the displacement are not in the same direction, we will calculate the work
done by the formula

W = Fs cos θ - - - 1

Given,
Force

F = 10 N

Magnitude of the displacement

s = 10 m

Angle between force and displacement,

θ = 60 °

Substituting these values in the above formula (1),
we get

W = (10) \times (10) \cos 60 °

W = 10 \times 10 \times \frac{1}{2} = 50

joule

(\cos 6 0^{0} = \frac{1}{2})

Work done by the child in pulling the toy car is given by

50 joule

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