A choke coil of resistance $5 Ω$ and inductance 0.6H is in series with a capacitance of $10 μF$ . If a voltage of 200 V is applied and the frequency is adjusted to resonance, the current and voltage across the inductance and capacitor are I₀, V₀, I₁ and V₁ respectively. We have

see full answer

Take the SCORE scholarship exam from home and compete for scholarships worth ₹1 crore!*

An Intiative by Sri Chaitanya

$V_{1} = 9 .8 kV$

$V_{1} = 19 .6 kV$

$V_{0} = 9 .8 kV$

$I_{0} = 40 A$

answer is A, B, C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Given voltage is 200V;

$L = 0 .6 H; C = 10^{- 5} F; R = 5 Ω$

in resonance condition, $Lω = \frac{1}{ωC} \Rightarrow X_{L} = X_{C}$

and the net impedance of the circuit is Z = R

$\Rightarrow$ the net current $i_{0} = \frac{V}{R} \Rightarrow i_{0} = 40 A$

The Potential drop across C and L is same.

$\begin{array}{l} V = {iX}_{L} = 40 A (Lω) = 40 A (\sqrt{6 \times 10^{4}}) Ω; \\ V = 9 .8 KV \end{array}$

Watch 3-min video & get full concept clarity