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Offline Centres

A chord of a circle of radius 10cm subtends a right angle at the center. Find the area of the corresponding Minor segment and major sector .

Use (π =3.14)

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28.5cm2 and 235.5 cm2

23.5 cm2 and 246.3cm2

45.3cm2 and 457.4 cm2

None of the above

answer is A.

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Detailed Solution

Area of minor segment APB = Area of Sector AOB – Area of △AOB

\frac{π \times 10 \times 10}{4} - (0.5 \times 10 \times 10)

78.5 - 50 = 28.5 cm

2
Area of major sector = Area of circle – Area of AOB

(π \times 10 \times 10) - \frac{π \times 10 \times 10}{4}

314 - 78.5 = 235.5 cm

2
Exam type - CBSE
Subject- Mathematics
Chapter - Circles
Topic-Equal Chords and their Distances from the Centre
Subtopic-Equal Chords and their Distances from the Centre

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