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Q.

A chord of a circle of radius 7cm subtends an angle of 90°at its centre. What is the ratio of areas of smaller and larger segments?


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a

2:7

b

1:10

c

1:11

d

none of these 

answer is B.

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Detailed Solution

Given, a chord of a circle of radius 7cm subtends an angle of 90°at its centre.
Area of minor segment =π×R24-12×R2 Area of minor segment =(π-2)4R2. . . . . . . . . . (1)
Area of major segment =πR2-(π-2)4R2 Area of major segment  =[4π-(π-2)]4R2
Area of major segment =3π+24R2. . . . . . . . . . . . (2)
Consider, equation (1)equation (2).
Required ratio =π-23π+2 Required ratio =880
Required ratio =110
So, the required ratio is 1:10.
Hence, option 2 is correct.
 
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A chord of a circle of radius 7cm subtends an angle of 90°at its centre. What is the ratio of areas of smaller and larger segments?