Q.

A chord P Q   whose length is 4.8 cm  , of a circle of radius 3 cm  . The tangents at P  and Q  intersect at a point T  as shown in the figure then the length of TP   is ____cm.


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Detailed Solution

A chord P Q   whose length is 4.8 cm  , of a circle of radius 3 cm  . The tangents at P  and Q  intersect at a point T  as shown in the figure then the length of TP   is 4cm.
Given that,
PQ=4.8 cm OP=3 cm  
Joining O   and Q  ,
Question ImageEquating between PTO   and OTQ  ,
OP=OQ   [Radii of the same circle]
PT=PQ  [Tangents from a same external point]
OT  is the common side,
Therefore by SSS congruency ΔPTO  and ΔOTQ   are congruent
And  PTO=OTQ   …..i)
Calculating the value of PR  using (i),
PTO=OTQ PT=PQ   [Tangents subtended by common external point]
RT  is a common side,
Therefore by SAS congruency rule ΔPRT   and ΔRTQ   are congruent.
PR=RQ= 1 2 PQ PR=PQ=2.4 cm  
Calculating the values of TR   and OR  ,
Applying Pythagoras theorem on ΔPRO   and using equation ii),
O P 2 =P R 2 +O R 2 3 2 = 2.4 2 +O R 2 OR= 95.76 OR= 3.24 OR=1.8.....iii)  
Applying Pythagoras theorem on ΔOPT  ,
O P 2 +P T 2 =O T 2 3 2 + T R 2 +P R 2 = (TR+OR) 2 9+5.76+T R 2 =T R 2 +3.24+2×1.8×TR 11.52=3.6TR TR=3.2.....iv)  
Calculating the value of PT  ,
Again applying the Pythagoras theorem on ΔPRT   and using equation iv),
P T 2 =T R 2 +P R 2 P T 2 = 3.2 2 + 2.4 2 P T 2 =16 PT=4  
Thus the length of PT  is 4 cm  .
 
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