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Q.

A chord PQ of a circle of radius 10 cm subtends an angle of 60° at the center of the circle. Find the area of the major and minor segment of the circle.

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a

A minor = 9.03 cm2, A major = 304.97 cm2

b

A minor = 500 cm2, A major = 400 cm2

c

A minor = 304.9 cm2, A major = 9.03 cm2

d

MOT

answer is A.

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Detailed Solution

Question Image

Radius r = 10 cm, Angle subtended θ = 60°
Area of OACB =

= 52.33 cm2
Now the area of ΔOAB

= 43.30 cm2
area of minor segment = area of sector
OACB – area of ΔOAB
ABC = 52.33 + 3.30
= 9.03 cm2
Now area of major sector = area of the circle – area of minor segment
ADB = 314 – 9.03
= 304.97 cm2
Hence, area of minor = 9.03 cm2
area of major = 304.97 cm2
So, option (A) is correct.

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