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Q.

A circle having centre at the origin passes through the three vertices of an equilateral triangle the length of its median being 9 units. Then the equation of that circle is

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a

x2+y2=9

b

x2+y2=18

c

x2+y2=36

d

x2+y2=81

answer is C.

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Detailed Solution

 Given centre of circle (C)=(0, 0)

and Length of median=9

  Now   radius=23(9)=6

Equation of circle is

   x2+y2=62    ⇒x2+y2=36

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