A circle is inscribed in a square given below. The area between the square and inscribed circle is

It is given that,
A circle is inscribed in a square.
From the graph,
It is clear that the diameter of the circle inscribed in the square is equal to the side of the square.
So,
Side of the square = 2 units. 
Then, 
Diameter of the Circle $\mathbf{=}\mathbf{d}\mathbf{=}\mathbf{2}\mathbf{\hspace{0.17em}}\mathbf{units}$ .  

$\Rightarrow \mathrm{Radius},\mathrm{\hspace{0.17em}}\mathrm{r}=\frac{\mathrm{d}}{2}=1\mathrm{\hspace{0.17em}}\mathrm{units}$ 
Therefore, 
From the graph,
The area between the circle and square = The area of the square - The area of the circle.  Then,
$\mathrm{Area}={\mathrm{Side}}^2-{\mathrm{\pi r}}^2\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\left\{\begin{array}{l}\mathrm{Area}\mathrm{\hspace{0.17em}}\mathrm{of}\mathrm{\hspace{0.17em}}\mathrm{Square}={\mathrm{Side}}^{\mathrm{2}}\\ \mathrm{Area}\mathrm{\hspace{0.17em}}\mathrm{of}\mathrm{\hspace{0.17em}}\mathrm{Circle}={\mathrm{\pi r}}^2\end{array}\right\}$ 
$\Rightarrow \text{Area}=2^2-\mathrm{\pi }{\left(1\right)}^2$ 
$\Rightarrow \text{Area}=4-3.14$ 
$\Rightarrow \mathrm{Area}=0.86\mathrm{\hspace{0.17em}}{\mathrm{unit}}^{\mathrm{2}}$ 
Hence, correct answer is $0.86\hspace{0.17em}{\mathrm{unit}}^{\mathrm{2}}$