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A circle of radius 7cm is cut into two pieces in the ratio $5 : 6$ , the smaller piece is bent into a rectangle in $3 : 2$ ratio, then its area of rectangle is $\dots \dots \dots$ sq. cm

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answer is D.

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Detailed Solution

$c = 2 \times \frac{22}{7} \times 7 = 44 cm$

Smaller piece $= \frac{5}{11} \times 44 = 20 cm$

Larger piece $= \frac{6}{11} \times 44 = 24 cm$

length $= 20 \times \frac{3}{10} = 6 cm$

breadth $= 20 \times \frac{2}{10} = 4 cm$

$A = l \times b = 6 \times 4 = 24 {cm}^{2}$

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