Q.

A circuit ABCD is held perpendicular to the uniform magnetic field of B=5×10-2Textending over the region PQRS and directed into the plane of the paper. The circuit is moving out of the field at a uniform speed of 0.2 ms-1 for 1.5 s. During this time, the current in the 5Ω resistor is

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a

0.9 mA from C to B

b

0.9 mA from B to C

c

`0.6 mA from C to B

d

0.6 mA from B to C

answer is A.

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Detailed Solution

I=BlvR

I=5×10-2×0.3×0.25A=0.6mA

Area and flux are decreasing. So, current flows to increase the flux. Clearly, current should be clockwise. So, it flows from .B
to C through 5Ω

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