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Q.

A circuit ABCD is held perpendicular to the uniform magnetic field of  B=5×102T  extending over the region PQRS and B directed into the plane of the paper. The circuit is moving out of the field at a uniform speed of 0.2 ms-1 for 1.5 s. During this time, the current in the 5Ω  resistor is

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a

0.9 mA from C to B

b

0.6 mA from C to B

c

0.9 mA from B to C

d

0.6 mA from B to C

answer is A.

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Detailed Solution

I=BlvR;  I=5×102×0.3×0.25A=0.6mA

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