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Q.

A circuit consists of two identical inductances, two identical resistors, and two identical capacitors, see figure. The applied voltage $U_{0} = 10 V;$ the voltage on the lower inductance is 10 V, and the voltage between the leads D and E is also 10V. Determine the voltage between the leads B and D.

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answer is 17.32.

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Detailed Solution

Phase diff between $V_{A B}$ and $V_{A D}$ is $120^{0}$ so. $V_{B D} = 10 \sqrt{3}$ volts.

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