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Q.

A circuit contains an ammeter, a battery of 30 V and a resistance 40.8 ohm all connected in series. If the ammeter has a coil of resistance 480 ohm and a shunt of 20 ohm, the reading in the ammeter will be

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a

1 A

b

0.5 A

c

2 A

d

0.25 A

answer is B.

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Detailed Solution

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(or)
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$R^{1} = \frac{480 \times 20}{480 + 20} = 19 .2 Ω$
$i = \frac{V}{R^{1} + R} = \frac{30}{19 .2 + 40 .8} = 0 .5 A$

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