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A circuit contains four cells $(C e l l - A, c e l l - B, C e l l - C a n d C e l l - D) .$ If $P_{A}, P_{B}, P_{C}$ and $P_{D}$ are the heat loss per unit time in the $C e l l - A, C e l l - B, C e l l - C a n d C e l l - D,$ respectively than chose correct statement.

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$P_{A} < P_{B} < P_{C} < P_{D}$

$P_{A} < P_{C} < P_{D} < P_{B}$

$P_{A} < P_{D} < P_{B} < P_{C}$

$P_{A} < P_{B} < P_{D} < P_{C}$

answer is D.

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Detailed Solution

$P_{A} = {(\frac{1}{2})}^{2} \times 2 P_{B} = {(1)}^{2} \times 2 P_{C} = {(1)}^{2} \times 4 P_{D} = {(1)}^{2} \times 3$

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