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Q.

A circular arc of radius 6 cm   has been drawn with vertex of an equilateral triangle of side 12 cm   as center and a sector of circle of radius 6 cm  with center B   is made. The area of the shaded region is ____ cm 2  . [Use 3 =1.73 and π=3.14.]  


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Detailed Solution

A circular arc of radius 6 cm has been drawn with vertex of an equilateral triangle of side 12 cm as center and a sector of circle of radius 6 cm with center B is made. The area of the shaded region is 137.64 cm2.
We know that,
Radius is 6cm and the vertex of the equilateral triangle is 12cm.
Draw the figure:
Question ImageArea of equilateral triangle = 3 4 × ( side ) 2  
Now, area of equilateral triangle ΔAOB  is-
= 3 4 × (AB) 2 = 1.73 4 (12) 2 =62.28  cm 2  
Area of sector of a circle having an angle θ   = θ 360 π r 2  
where, r   is the radius of the circle and θ   is the sector angle.
 And, area of sector having central angle 60° is-
= 60 360 × 22 7 × 6 2 = 1 6 ×3.14×36 =18.84  cm 2    Also, area of sector having central angle 360 ° 60 °   is-
= 300 360 × 22 7 × 6 2 = 5 6 ×3.14×36 =94.2  cm 2  
Therefore, area of the shaded region is-
= (Area of ΔAOB  − Area of sector having central angle 60°) + Area of sector having central angle (360° − 60°)
=62.818.84+94.2 =137.64  cm 2  
Hence, the area of the shaded region is 137.64 cm 2  .
 
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