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Q.

A circular coil 'A' has a radius R and the current flowing through it is I. Another circular coil 'B' has a radius 2R and if 2I is the current flowing through it, then the magnetic fields at the Centre of the circular coil are in the ratio of

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a

$4 : 1$

b

$2 : 1$

c

$3 : 1$

d

$1 : 1$

answer is D.

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Detailed Solution

$B_{1} = \frac{μ_{0} i}{2 R}$

$B_{2} = \frac{μ_{0} 2 i}{2 x 2 R} = \frac{μ_{0} i}{2 R}$

$B_{1} = B_{2}$

$\Rightarrow B_{1} : B_{2} = 1 : 1$

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