A circular coil of radius R and N turns carrying current I is in y-z plane, If it carries current in anticlock wise sense when viewed from top, the magnitude of the magnetic field at a point on its axis at a distance x from its centre is given by

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$[\frac{μ_{0} {IR}^{2} N}{4 {(x^{2} + R^{2})}^{3 / 2}}] \hat{k}$

$[\frac{μ_{0} {IR}^{2} N}{2 {(x^{2} + R^{2})}^{3 / 2}}] \hat{j}$

$[\frac{μ_{0} {IR}^{2} N}{2 π {(x^{2} + R^{2})}^{3 / 2}}] \hat{i}$

$[\frac{μ_{0} {IR}^{2} N}{2 {(x^{2} + R^{2})}^{3 / 2}}] \hat{i}$

answer is D.

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Detailed Solution

$B_{A} = \frac{μ_{0} {NIR}^{2}}{2 {(R^{2} + x^{2})}^{3 / 2}} (\hat{i})$

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