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A circular curve of a highway is designed for traffic moving at 72 km/h. If the radius of the curved path is 100 m, the correct angle of banking of the road should be

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$\tan^{- 1} (\frac{1}{4})$

$\tan^{- 1} (\frac{3}{5})$

$\tan^{- 1} (\frac{1}{5})$

$\tan^{- 1} (\frac{2}{5})$

answer is A.

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Detailed Solution

v = 72 km/h = 72 $\times \frac{5}{18}$ m/s = 20 m/s

$θ = \tan^{- 1} (\frac{v^{2}}{R g})$

= $\tan^{- 1} (\frac{400}{100 \times 10})$ = $\tan^{- 1} (\frac{2}{5})$

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