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Q.

A circular disc is rotating about its own axis. An external opposing torque 0.02Nm is applied on the disc by which it comes to rest in 5 seconds. The initial angular momentum of disc is

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a

0.01kgm2s−1

b

0.04kgm2s−1

c

0.025kgm2s−1

d

0.1kgm2s−1

answer is A.

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Detailed Solution

τ=0.02Nm

t=5sL1=? L2=0

τ=L2−L1t

0.02=0−L15,L1=0.1kgm2s−1

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