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Q.

A circular disc of mass ‘M’ and radius ‘R’ is rolling on a horizontal surface starts ascending a smooth inclined plane. If the velocity of centre of mass of disc at the bottom of inclined plane is 20 m/s, then maximum height to which it can reach is $(g = 10 m / s^{2})$

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a

20 m

b

cannot ascend

c

30 m

d

40 m

answer is A.

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Detailed Solution

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$\frac{1}{2} m v^{2} = m g h$

$h = \frac{v^{2}}{2 g} = \frac{{(20)}^{2}}{20} = 20 m$

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A circular disc of mass ‘M’ and radius ‘R’ is rolling on a horizontal surface starts ascending a smooth inclined plane. If the velocity of centre of mass of disc at the bottom of inclined plane is 20 m/s, then maximum height to which it can reach is (g=10 m/s2)