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Q.

A circular hole of diameter d =10 cm is to be punched out of a plate having an ultimate shearing stress, σs=2×108pa  as shown in figure. If the maximum compressive stress on the punch is limited to  σc=4×108pa .The maximum thickness ‘t’ (in cm) of the plate in which punch can be made

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answer is 5.

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Detailed Solution

Shear area = πdt   of the plate 
   Maximum shear force = σsπdt;  area of cross-section of Punch = πd24  
  Maximum normal force on Punch =  πd24σc  σsπdt=σcπd24;  t=σcd4σs

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