A circular loop which is in the form of a major arc of a circle is kept in the horizontal plane and a constant magnetic field. B is applied in the vertical direction such that the magnetic lines of forces go into the plane. If R is the radius of circle and it carries a current I in the clockwise direction, then the force on the loop will be

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$2 B I R \cos (α / 2)$

$B I R \tan α$

$2 B I R \sin α$

$2 B I R \sin (α / 2)$

answer is C.

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Detailed Solution

$A B = 2 R \sin \frac{α}{2} ∴ F o r c e = I B (2 R \sin \frac{α}{2}) = 2 B I R \sin (\frac{α}{2})$

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