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A circular of radius 1 dm is cut and is placed along the circumference of a circle

of the radius of 1m. The angle subtended by wire at the centre of the radius is equal to

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\frac{Π}{4}

radian

\frac{Π}{3}

radian

\frac{Π}{5}

radian

\frac{Π}{10}

radian

answer is C.

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Detailed Solution

Length of wire =2π

\times

1 = 2π
Radius of circle =1m =10dm
Angle required =

\frac{arc}{radius}

\frac{2 π}{10}

\frac{π}{5}

radian

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A circular of radius 1 dm is cut and is placed along the circumference of a circle of the radius of 1m. The angle subtended by wire at the centre of the radius is equal to

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A circular of radius 1 dm is cut and is placed along the circumference of a circle

of the radius of 1m. The angle subtended by wire at the centre of the radius is equal to