A circular platform is free to rotate in a horizontal plane about a vertical axis passing through it's center. Its radius R=2m and its moment of inertia about the axis is $200 k g m^{2}$ . It is initially at rest. A 50 kg man stands on the edge of the platform and begins to walk along the edge at the speed of $1 m s^{- 1}$ relative to the ground. Time taken by the man to complete one revolution is $\frac{λ π}{10} \sec$ then the value of $λ$ is______

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Detailed Solution

$0 = (50) (1) (2) - 200 ω ω = \frac{1}{2} r a d / s v_{r e l} = 1 + 2 (\frac{1}{2}) = 2 T = \frac{(2 π) (2)}{2} = 2 π s$

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